集中练习6-bash脚本

集中练习6-bash脚本

1. 写一个脚本,使用ping命令探测172.16.250.1-172.15.250.254之间所有主机的在线状态;在线的主机使用绿色显示;不在线的主机使用红色显示
“`
#!/bin/bash
#
for i in {1..254}; do
ping 172.16.250.$i -w 1 -c 1 &> /dev/null
RETVAL=$?
if [ $RETVAL -eq 0 ]; then
echo -e “\033[32mHost 172.16.250.$i is online.\033[0m ”
else
echo -e “\033[31mHost 172.16.250.$i is offline.\033[0m ”
fi
done
“`
2. 如何给网络配置多个地址,有哪些方式?
“`
(1) 通过ip命令添加
~]# ip addr add <IP_ADDR>/<MASKLEN> dev <IFACE_NAME>
(2) 针对CentOS7,使用nmtui命令添加
(3) 使用ifconfig命令
~]# ifconfig IFACE_LABEL IPADDR/NETMASK
(4) 可以通过复制原有配置文件到新文件IFACE:0,然后修改IP地址,网卡别名不支持动态获取地址
“`
3. 写一个脚本,完成以下功能
(1) 假设某目录(/etc/rc.d/rc3.d)下分别有K开头的文件和S开头的文件若干;
(2) 显示所有以K开头的文件的文件名,并且给其附加一个stop字符串;
(3) 显示所有以S开头的文件的文件名,并且给其附加一个start字符串;
(4) 分别统计S开头和K开头的文件各有多少?
“`
#!/bin/bash
#
declare -i numk=0
declare -i nums=0
for files in `ls /etc/rc.d/rc3.d`; do
if [[ $files =~ ^K[[:digit:]].* ]]; then
echo “$files stop.”
let numk+=1
elif [[ $files =~ ^S[[:digit:]].* ]]; then
echo “$files start.”
let nums+=1
fi
done
echo “The number for Kfiles is $numk.”
echo “The number for Sfiles is $nums.”
“`
4. 写一个脚本,完成以下功能
(1) 脚本能接受用户名作为参数;
(2) 计算此些用户的ID之和;
“`
#!/bin/bash
#
echo -e “This is a script for calculate the summation for the user UID you entered, you can enter as many times as you want until you enter quit, and the script will calculate the summation for all these users’ UID for you. \n”
read -p “Please enter a username: ” user
declare -i sum=0
until [ $user == ‘quit’ ]; do
if id $user &> /dev/null; then
declare -i UserID=`id -u $user`
let sum+=$UserID
read -p “Please reenter a username: ” user
else
echo “User $user does not exist.”
read -p “Please reenter a username: ” user
fi
done
echo “The summation of UID for all the users you entered is $sum.”
“`
5. 写一个脚本
(1) 传递一些目录给此脚本;
(2) 逐个显示每个目录的所有一级文件或子目录的内容类型;
(3) 统计一共有多少个目录,且一共显示了多少个文件的内容类型;
“`
#!/bin/bash
#
[ -e /tmp/filetype.txt ] && rm -f /tmp/filetype.txt
read -p “Please enter a directory: ” dirc
declare -i typenum=0
declare -i dircnum=0
until ls $dirc &> /dev/null; do
echo “The directory you entered does not exist.”
read -p “Please enter a directory: ” dirc
done
touch /tmp/filetype.txt
until [ $dirc == ‘quit’ ]; do
let dircnum+=1
for dir_file in `ls $dirc`; do
file_type=`file -b $dirc/$dir_file | cut -d’,’ -f1`
echo $file_type | grep “symbolic link” &> /dev/null && file_type=’symbolic link’
cat /tmp/filetype.txt | grep “$file_type” &> /dev/null
RETVAL=$?
if [ $RETVAL -ne 0 ]; then
echo $file_type >> /tmp/filetype.txt
let typenum+=1
fi
done
read -p “Please enter a directory: ” dirc
done
echo “You totally entered $dircnum directories.”
echo “There are $typenum types of file in the directories you entered.”
rm -f /tmp/filetype.txt
“`
6. 写一个脚本
(1) 通过命令行传递一个参数给脚本,参数为用户名;
(2) 如果用户的id号大于等于500,则显示此用户为普通用户;
“`
#!/bin/bash
#
read -p “Please enter a user: ” user
until [ $user == ‘quit’ ]; do
if ! id $user &> /dev/null; then
echo “The user you entered doesn’t exist.”
read -p “Please enter a user: ” user
else
declare -i UserID=`id -u $user`
if [ $UserID -ge 500 ]; then
echo “User $user is a common user.”
fi
read -p “Please enter a user: ” user
fi
done
“`
7. 写一个脚本,用ping命令测试172.16.250.20-172.16.250.100之间有哪些主机在线,将在线的显示出来;
“`
#!/bin/bash
#
for i in {20..100};do
ping -c 1 -W 1 172.16.250.$i &> /dev/null
RETVAL=$?
if [ $RETVAL -eq 0 ]; then
echo “Host 172.16.250.$i is online.”
fi
done
“`
8. 打印九九乘法表;

for循环
“`
#!/bin/bash
#
for a in {1..9}; do
for b in `seq 1 $a`; do
echo -n -e “${b}X${a}=$[${b}*${a}]\t”
done
echo
done
“`
while循环
“`
#!/bin/bash
#
declare -i a=1

while [ $a -le 9 ]; do
declare -i b=1
while [ $b -le $a ]; do
echo -n -e “${b}X${a}=$[${b}*${a}]\t”
let b++
done
let a++
echo
done
“`
until循环
“`
#!/bin/bash
declare -i a=1

until [ $a -gt 9 ]; do
declare -i b=1
until [ $b -gt $a ]; do
echo -n -e “${b}X${a}=$[${b}*${a}]\t”
let b++
done
let a++
echo
done
“`
9. 打印逆序的九九乘法表;

for循环
“`
#!/bin/bash
#
for a in `seq 1 9 | sort -r`; do
for b in `seq 1 $a | sort -r`; do
echo -n -e “${b}X${a}=$[${b}*${a}]\t”
done
echo
done
“`
while循环
“`
#!/bin/bash
#
declare -i a=9
while [ $a -ge 1 ]; do
declare -i b=$a
while [ $b -ge 1 ]; do
echo -n -e “${b}X${a}=$[${b}*${a}]\t”
let b–
done
let a–
echo
done
“`
until循环
“`
#!/bin/bash
#
declare -i a=9
until [ $a -lt 1 ]; do
declare -i b=$a
until [ $b -lt 1 ]; do
echo -n -e “${b}X${a}=$[${b}*${a}]\t”
let b–
done
let a–
echo
done
“`

本文来自投稿,不代表Linux运维部落立场,如若转载,请注明出处:http://www.178linux.com/89523

赞 (0)
N27_sapbcsN27_sapbcs
上一篇 2017-12-04 21:20
下一篇 2017-12-05 10:53

相关推荐

  • linux学习总结-linux基础(之一)

    一、计算机的组成及其功能 冯诺依曼结构的计算机由运算器、控制器、存储器和输入设备、输出设备五部分组成。冯诺依曼理论的要点是:数字计算机的数制采用二进制;计算机应该按照程序顺序执行。 控制器:控制程序执行; 存储器:记忆程序和数据; 输入设备:输入数据和程序; 输出设备:输出处理结果。 二、Linux发行版 Linux的发型版本众多,大体可以分为两类,一类是商…

    Linux干货 2016-09-23
  • 马哥教育网络班21期+第5周课程练习

    1、显示/boot/grub/grub.conf中以至少一个空白字符开头的行; [root@centos ~]# grep "^[[:space:]]\+" /boot/grub/grub.conf  root (hd0,0) kernel /vmlinuz-2.6.3…

    Linux干货 2016-07-29
  • shell脚本编程之if、case条件语句

    程序执行三种顺序     顺序执行          选择执行          循环执行       &nb…

    Linux干货 2016-08-18
  • 马哥教育网络班21期-第九周课程练习

    "1、写一个脚本,判断当前系统上所有用户的shell是否为可登录shell(即用户的shell不是/sbin/nologin);分别这两类用户的个数;通过字符串比较来实现; #!/bin/bash # declare -i login_user=0 declare -i nologin_user=0 whil…

    Linux干货 2016-09-15
  • mysql编译安装

    MYSQL编译安装:参考(http://v.youku.com/v_show/id_XMjc4MDUwNjYyOA==.html?from=s1.8-1-1.2&spm=a2h0k.8191407.0.0)(http://oldboy.blog.51cto.com/2561410/1917295)     编译安装mysql,最好…

    Linux干货 2017-06-09
  • yum源设置

      yum是我们经常用到的一个程序,我们主要用它来安装或删除安装包,下面我来介绍一下怎样配置yum安装源?    配置yum安装源主要有两种方法:一种是用本地镜像做安装源,二是用提供镜像下载的网站做安装源。    一 配置本地安装源    本地安装源需要有系统镜像,操作步骤如下:…

    Linux干货 2016-01-16

评论列表(1条)

  • 马哥教育
    马哥教育 2017-12-08 16:40

    脚本没有问题,建议排版可以截图下来。不然不好分析,也不好看。